The correct relationship between the displacement, s, of a particle initially at rest in a linear motion and the time, t, is?
- s \(\alpha\) t\(^{-2}\)
- s \(\alpha\) t\(^{-1}\)
- s \(\alpha\) t
-
s \(\alpha\) t\(^{2}\)
The correct answer is: D
Explanation
Mathematically; S = vt + \(\frac{1}{2}\) at\(^2\)
: S ∝ t\(^2\)