The most appropriate value of fuse for a kettle rated 220 V, 1.06 kW is
- 3A
- 6A
-
5A
- 4A
The correct answer is: C
Explanation
V = 220V, P = 1.60KW = 1060W, I = ?
P = IV
I = \(\frac{P}{V} = \frac{1060}{220}\)
≈ 5A.