A sound of frequency 512 Hz reaches a listener 100 m away. If the sound travels in air at s.t.p., what is its wavelength?
[speed of sound in air = 331 m/s]
- 1.550m
-
0,646m
- 5.120m
- 0.195m
The correct answer is: B
Explanation
f = 512Hz, V = 331m/s λ = ?
V = f λ
λ = \(\frac{v}{f} = \frac{331}{512}\)
λ = 0.646m.