A particle of mass 3.6 x 10\(^{-6}\)kg revolving around the earth has a radial acceleration of 4.3 x 10\(^7\)ms\(^{-2}\). Calculate the centripetal force of the particle.
-
1.55 x 10\(^2\)N
- 2.00 x 10\(^{-2}\)N
- 6.25 x 10\(^{-14}\)N
- 1.00 x 10\(^2\)N
The correct answer is: A
Explanation
F = mass x acceleration due to gravity
F\(_c\) = m x a\(_c\)
a\(_c\) = a\(_r\) = 4.3 x 10\(^7\)ms\(^{-2}\), m = 3.6 x 10\(^{-6}\)kg
F\(_c\) = m x a\(_c\) = 3.6 x 10\(^{-6}\) x 4.3 x 10\(^7\) = 154.8N ≈ 155N ⇒ 1.55 x 10\(^2\)N