A constant voltage source supplies a sinusoidal alternating e.m.f. The voltage marked against the components are their peak values. Determine the peak value of the applied e.m.f
- 1V
- 4V
-
5V
- 2V
The correct answer is: C
Explanation
Effective voltage in an RLC circuit is given by V = \(\sqrt{V_R^2 + (V_L - V_C)^2}\)
V = \(\sqrt{3^2 + (6 - 2)^2}\) = \(\sqrt{3^2 + 4^2}\) = \(\sqrt{9 + 16}\)
= 5V